vsepr theory - How do I figure out the hybridization of a particular ...
2013年3月17日 · Trigonal bipyramidal - $\ce{dsp^3}$ or $\ce{sp^3d}$ - the hybridization of one $\ce{s}$, three $\ce{p}$, and one $\ce{d}$ orbitals produce five hybrid orbitals oriented in this …
What is the chemical structure / hybridization of sulfuric acid?
2012年8月27日 · This was a source of confusion that goes back to Gilbert Lewis who originally proposed the below structure fitting of a sp3 hybridization (model 2): Linus Pauling steps in to …
Why is [PdCl4]2- square planar whereas [NiCl4]2- is tetrahedral?
If $\Delta E < P + S$, then the complex will be tetrahedral. This is analogous to deciding whether an octahedral complex adopts a high- or low-spin configuration; where the crystal field splitting …
Why is tetraamminecopper(II) a square planar and not a …
2015年7月23日 · All Cupric complexes irrespective of the kind of ligands is always dsp2 square planar hybridization . Now the question is that why this is so? In tetrahedral complexes when …
inorganic chemistry - How can the hybridisation schemes of …
In traditional hybridisation theory, tetrahedral and square planar 4-coordinate complexes are considered to be $\mathrm{sp^3}$ and $\mathrm{dsp^2}$ respectively. Since $\ce{[Ni(CO)4]}$ …
bond - Why is it wrong to use the concept of hybridization for ...
2017年6月24日 · Tetrahedral complexes Let's consider, for example, a tetrahedral $\ce{Ni(II)}$ complex ( $\mathrm{d^8}$ ), like $\ce{[NiCl4]^2-}$ . According to hybridisation theory, the …
Tetrahedral or Square Planar - Chemistry Stack Exchange
2013年4月12日 · $\ce{Ni^{+2}}$ produces a square planar complex with $\ce{CN-}$, as cyanide is a strong ligand. Nickel carbonyl, on the other hand, exists as a tetrahedral complex because …
dsp2 and sp3 hybrid orbital shapes in coordination chemistry
2016年3月6日 · Why is $\\mathrm{dsp}^2$ square planar but $\\mathrm{sp}^3$ tetrahedral in shape? I am unable to find a reason anywhere. I know how to figure which hybridisation a …
coordination compounds - Why is tetracyanonickelate square …
2014年12月22日 · It's tetrahedral; as not 6 lone pairs are coming from $\ce{CN}$, only $\ce{CN}$ are attached. Therefore, only 4 lone pairs will affect the configuration. So by now applying CFT …
hybridization - Possible structure if a compound like AB4 is polar ...
2020年9月3日 · The derivative of (A), option (B) rectangular planar, as well as option (D) tetrahedral also refer to the environments that posses zero dipole moment. Speaking of (C), I …